# C: printf a float value

###### Posted By: Anonymous

I want to print a float value which has 2 integer digits and 6 decimal digits after the comma. If I just use `printf("%f", myFloat)`

I’m getting a truncated value.

I don’t know if this always happens in C, or it’s just because I’m using C for microcontrollers (CCS to be exact), but at the reference it tells that `%f`

get just that: a truncated float.

If my float is `44.556677`

, I’m printing out `"44.55"`

, only the first two decimal digits.

So the question is… how can I print my 6 digits (and just the six of them, just in case I’m having zeros after that or something)?

## Solution

You can do it like this:

```
printf("%.6f", myFloat);
```

6 represents the number of digits after the decimal separator.

###### Answered By: Anonymous

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