Posted By: user269857
I’m a new Python programmer who is making the leap from 2.6.4 to 3.1.1. Everything has gone fine until I tried to use the ‘else if’ statement. The interpreter gives me a syntax error after the ‘if’ in ‘else if’ for a reason I can’t seem to figure out.
def function(a): if a == '1': print ('1a') else if a == '2' print ('2a') else print ('3a') function(input('input:'))
I’m probably missing something very simple; however, I haven’t been able to find the answer on my own.
In python “else if” is spelled “elif”.
Also, you need a colon after the
elif and the
Simple answer to a simple question. I had the same problem, when I first started (in the last couple of weeks).
So your code should read:
def function(a): if a == '1': print('1a') elif a == '2': print('2a') else: print('3a') function(input('input:'))